70-761 試験問題 & 70-761 資格受験料

 

Microsoftの70-761 試験問題を受験したいですか。試験がたいへん難しいですから悩んでいるのですか。試験を申し込みたいですが、合格できないことが心配します。いまこのような気持ちを持っていますか。大丈夫ですよ。安心に70-761 試験問題を申し込みましょう。JapanCertの試験参考書を使用する限り、どんなに難しい試験でも問題にならないです。試験に合格する自信を全然持っていなくても、JapanCertの70-761 試験問題はあなたが一度簡単に成功することを保証できます。不思議と思っていますか。では、JapanCertのウェブサイトへ来てもっと多くの情報をブラウズすることもできます。それに、70-761 試験問題の一部を試用することもできます。そうすると、この参考書が確かにあなたが楽に試験に合格する保障ということをきっと知るようになります。

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70-761試験番号:70-761 対応資料
試験科目:「Querying Data with Transact-SQL
最近更新時間:2017-06-14
問題と解答:60

>> 70-761 対応資料

 

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NO.1 DRAG DROP
Note: This question is part of a series of questions that use the same scenario. For your convenience,
the scenario is repeated in each question. Each question presents a different goal and answer
choices, but the text of the scenario is exactly the same in each question on this series.
You have a database that tracks orders and deliveries for customers in North America.
System versioning is enabled for all tables. The database contains the Sales.Customers,
Application.Cities, and Sales.CustomerCategories tables.
Details for the Sales.Customers table are shown in the following table:
Details for the Application.Cities table are shown in the following table:
Details for the Sales.CustomerCategories table are shown in the following table:
You are preparing a promotional mailing. The mailing must only be sent to customers in good
standing that live in medium and large cities.
You need to write a query that returns all customers that are not on credit hold who live in cities with
a population greater than 10,000.
How should you complete the Transact-SQL statement? To answer, drag the appropriate
Transact-SQL segments to the correct locations. Each Transact-SQL segment may be used once, more
than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: IN (
The IN clause determines whether a specified value matches any value in a subquery or a list.
Syntax: test_expression [ NOT ] IN ( subquery | expression [ ,...n ] )
Where subquery
Is a subquery that has a result set of one column. This column must have the same data type as
test_expression.
Box 2: WHERE
Box 3: AND [IsOnCreditHold] = 0
Box 4: )
References: https://msdn.microsoft.com/en-us/library/ms177682.aspx

NO.2 HOTSPOT
Note: This question is part of a series of questions that use the same scenario. For your convenience,
the scenario is repeated in each question. Each question presents a different goal and answer
choices, but the text of the scenario is exactly the same in each question in this series.
You query a database that includes two tables: Project and Task. The Project table includes the
following columns:
You need to identify the owner of each task by using the following rules:
- Return each task's owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project's owne
r.
- Return the value -1 for all other cases.
How should you complete the Transact-SQL statement? To answer, select the appropriate
Transact-SQL segments in the answer area.
Answer:
Explanation:
Box 1: COALESCE
COALESCE evaluates the arguments in order and returns the current value of the first expression that
initially does not evaluate to NULL.
Box 2: T.UserID, p.UserID, -1
- Return each task's owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project's owne
r.
- Return the value -1 for all other cases.
Box 3: RIGHT JOIN
The RIGHT JOIN keyword returns all rows from the right table (table2), with the matching rows in the
left table (table1). The result is NULL in the left side when there is no match.
Here the right side could be NULL as the projectID of the task could be NULL.
References:
https://msdn.microsoft.com/en-us/library/ms190349.aspx
http://www.w3schools.com/Sql/sql_join_right.asp

NO.3 Note: This question is part of a series of questions that present the same scenario. Each
question in the series contains a unique solution that might meet the stated goals. Some question
sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section. you will NOT be able to return to it. As a result, these
questions will not appear in the review screen.
You create a table named Customer by running the following Transact-SQL statement:
You must insert the following data into the Customer table:
You need to ensure that both records are inserted or neither record is inserted.
Solution: You run the following Transact-SQL statement:
Does the solution meet the goal?
A. Yes
B. No
Answer: B

70-761 費用   70-761 模試   
Explanation:
As there are two separate INSERT INTO statements we cannot ensure that both or neither records is
inserted.

NO.4 Note: This question is part of a series of questions that present the same scenario. Each
question in the series contains a unique solution that might meet the stated goals. Some question
sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section. you will NOT be able to return to it. As a result, these
questions will not appear in the review screen.
You have a database that tracks orders and deliveries for customers in North America. The database
contains the following tables:
Sales.Customers
Application.Cities
Sales.CustomerCategories
The company's development team is designing a customer directory application. The application
must list customers by the area code of their phone number. The area code is defined as the first
three characters of the phone number.
The main page of the application will be based on an indexed view that contains the area and phone
number for all customers.
You need to return the area code from the PhoneNumber field.
Solution: You run the following Transact-SQL statement:
Does the solution meet the goal?
A. No
B. Yes
Answer: A

70-761 絶対   70-761 通信   
Explanation:
The variable max, in the line DECLARE @areaCode nvarchar(max), is not defined.

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